2x^2-21x+480=0

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Solution for 2x^2-21x+480=0 equation:


Simplifying
2x2 + -21x + 480 = 0

Reorder the terms:
480 + -21x + 2x2 = 0

Solving
480 + -21x + 2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
240 + -10.5x + x2 = 0

Move the constant term to the right:

Add '-240' to each side of the equation.
240 + -10.5x + -240 + x2 = 0 + -240

Reorder the terms:
240 + -240 + -10.5x + x2 = 0 + -240

Combine like terms: 240 + -240 = 0
0 + -10.5x + x2 = 0 + -240
-10.5x + x2 = 0 + -240

Combine like terms: 0 + -240 = -240
-10.5x + x2 = -240

The x term is -10.5x.  Take half its coefficient (-5.25).
Square it (27.5625) and add it to both sides.

Add '27.5625' to each side of the equation.
-10.5x + 27.5625 + x2 = -240 + 27.5625

Reorder the terms:
27.5625 + -10.5x + x2 = -240 + 27.5625

Combine like terms: -240 + 27.5625 = -212.4375
27.5625 + -10.5x + x2 = -212.4375

Factor a perfect square on the left side:
(x + -5.25)(x + -5.25) = -212.4375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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